The function to be maximized is given by $Z=2 x+y$. The feasible region for this function $Z$ is the shaded…

The function to be maximized is given by $Z=2 x+y$. The feasible region for this function $Z$ is the shaded region given below. The maximum value of $Z$ is and occurs at the point
.
  1. $10,(5,0)$
  2. $12,(6,0)$
  3. $9,(1.5,6)$
  4. $21,(0.5,0)$

Solution

Corner points are $(0,5),(5,0),(6,0),(0,7)$ and $\left(\frac{3}{2}, 6\right)$ $Z=2 x+y$ is maximum at $(6,0)$ $Z_{\max }=2 \times 6+0=12$

Asked in: MHT CET 2022 (08 Aug Shift 2)

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