The function $f(x)=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-7 x+5}}$ has discontinuous points at $\mathrm{x}=$
The function $f(x)=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-7 x+5}}$ has discontinuous points at $\mathrm{x}=$
$5 / 2,2$
$-1 / 3,2$
$1,5 / 2$
$-1 / 3,1$
Solution
Given the function $f(x)=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-7 x+5}}$
$=\sqrt{\frac{3 x^2-5 x-2}{2 x^2-2 x-5 x+5}}=\sqrt{\frac{3 x^2-5 x-2}{(2 x-5)(x-1)}}$
So given function is discontinuous at $x=1, \frac{5}{2}$