The function f x = 4 x 3 - 3 x 2 6 - 2 sin x + 2 x - 1 cos x :

The function fx=4x3-3x26-2sinx+2x-1cosx:
  1. increases in 12,
  2. decreases in -,12
  3. decreases in 12,
  4. increases in -,12

Solution

fx=4x3-3x26-2sinx+2x-1cosx

f'x=2x2-x-2cosx+2cosx-sinx2x-1.

=2x-1x-sinx

for x>0,x-sinx>0

x<0,x-sinx<0

for x-,012,,f'x0

for x0,12,f'x0

 fx increases in 12,

Asked in: JEE Main 2021 (24 Feb Shift 1)

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