The frequency of a tuning fork with amplitude $A = 1\text{ cm}$ is $250\text{ Hz}$. The maximum velocity of…
The frequency of a tuning fork with amplitude $A = 1\text{ cm}$ is $250\text{ Hz}$. The maximum velocity of any particle in air is equal to
- 10$\pi$ ms$^{-1}$
- 5$\pi$ ms$^{-1}$
- 2$\pi$
- None of these
Solution
Maximum particle velocity,
$(v_P)_{\text{max}} = \omega A = 2\pi fA$
$= 2\pi (250) (10^{-2}) = 5\pi\text{ ms}^{-1}$
Practice more Waves and Sound questions on Aicharya