The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} /…

The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled is
  1. $120 \mathrm{~m}$
  2. $60 \mathrm{~m}$
  3. $53 \mathrm{~m}$
  4. $100 \mathrm{~m}$

Solution

$\begin{aligned} & \mathrm{f}=220 \mathrm{~Hz}, v=330 \mathrm{~m} / \mathrm{s} \\ & v=\mathrm{f} \lambda \\ & \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{330}{220}=\frac{3}{2} \mathrm{~m} \end{aligned}$ Distance travel in 80 vibrations $=80 \times \frac{3}{2}=120 \mathrm{~m}$ ^

Asked in: MHT CET 2021 (24 Sep Shift 1)

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