The freezing point of equimolal aqueous solution will be highest for

The freezing point of equimolal aqueous solution will be highest for
  1. $C_{6} \mathrm{H}_{5} \mathrm{NH}_{3}^{+} \mathrm{Cl}^{-}$(aniline hydrochloride)
  2. $\mathrm{Ca}\left(\mathrm{NO}_{3}ight)_{2}$
  3. $\mathrm{La}\left(\mathrm{NO}_{3}ight)_{3}$
  4. $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ (glucose)

Solution

$\mathrm{La}\left(\mathrm{NO}_{3}ight)_{3}$ will furnish four ions and thus will develop more lowering in freezing point whereas glucose gives only one particle and thus minimum lowering in freezing point. ^

Asked in: JEE-TOPICTESTS-CHEMISTRY

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