The freezing point of benzene decreases by ${0.45}^{°} C$ on adding $0.2 g$ of acetic acid to $20 g$ of benzene. If acetic acid associates to form a dimer in benzene, then what is the percentage association of acetic acid in benzene?
$(K_{f} for benzene = 5 .12 K kg {mol}^{- 1})$

Question

The freezing point of benzene decreases by ${0.45}^{°} C$ on adding $0.2 g$ of acetic acid to $20 g$ of benzene. If acetic acid associates to form a dimer in benzene, then what is the percentage association of acetic acid in benzene?

$(K_{f} for benzene = 5 .12 K kg {mol}^{- 1})$

Aicharya · Accepted Answer

2 CH 3 COOH &#8652; CH 3 COOH 2 1 - &#945; &#945; 2 i = 1 - &#945; 2 &#916;T f = i &#215; K f &#215; m 0 .45 = i &#215; 5 .12 &#215; 0 .2 &#215; 1000 60 &#215; 20 i = 0 .527 = 1 - &#945; 2 &#160; &#8658; &#945; = 0 .946 or 94 . 6 %

The freezing point of benzene decreases by 0.45 ° C on adding 0 . 2   g of acetic acid to 20 &#160…

Solution

The freezing point of benzene decreases by 0.45 &#176; C on adding 0 . 2 &#160; g of acetic acid to 20 &#160…

Solution

The freezing point of benzene decreases by 0.45 ° C on adding 0 . 2 g of acetic acid to 20 &#160…