The freezing point of a 4 % aqueous solution of X is equal to the freezing point of a 12 % aqueous solution of Y . If the molecular weight of X is A , then the molecular weight of Y will be

Question

Aicharya · Accepted Answer

Freezing point depression refers to the lowering of the freezing point of solvent upon the addition of solute.
${({ΔT}_{f})}_{X} = {({ΔT}_{f})}_{Y}$

$k_{f} m_{x} = k_{f} m_{y}$

$\frac{4 \times 1000}{A \times 96} = \frac{12 \times 1000}{M \times 88}$

$M = 3 .27 A$

$≃ 3 A$

The freezing point of a 4 % aqueous solution of X is equal to the freezing point of a 12 % aqueous solution…

Solution