The formula of the product formed, when sodium thiosulphate solution is added to silver bromide is

The formula of the product formed, when sodium thiosulphate solution is added to silver bromide is
  1. $\mathrm{Ag}_2 \mathrm{~S}_2 \mathrm{O}_3$
  2. $\mathrm{Ag}_2 \mathrm{~S}$
  3. $\mathrm{Na}_3\left[\mathrm{Ag}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right]$
  4. $\mathrm{Ag}_3\left[\mathrm{Na}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right]$

Solution

When sodium thiosulphate solution is added to $\mathrm{AgBr}$, then sodium argentothiosulphate is obtained. $\begin{aligned} & \mathrm{AgBr}+2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3 \longrightarrow \mathrm{Na}_3\left[\mathrm{Ag}\left(\mathrm{S}_2 \mathrm{O}_3\right)_2\right] \\ & \text { (colourless) } \\ & \text { sodium argentothiosulphate } \\ & +\mathrm{NaBr} \\ & \end{aligned}$

Asked in: AP EAMCET 2007

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