The force of repulsion between two electrons at a certain distance is $\mathrm{F}$. The force between two…

The force of repulsion between two electrons at a certain distance is $\mathrm{F}$. The force between two protons separated by the same distance is $\left(\mathrm{m}_{\mathrm{p}}= 1836 \mathrm{~m}_{\mathrm{e}}\right)$
  1. $2 \mathrm{~F}$
  2. $\mathrm{F}$
  3. $1836 \mathrm{~F}$
  4. $\frac{\mathrm{F}}{1836}$

Solution

Electrostatic force is given by $\mathrm{F}=\frac{1}{4 \pi \varepsilon_{0}} \frac{\mathrm{q}_{1} \mathrm{q}_{2}}{\mathrm{r}^{2}}$
Here, charge and distance are same. So, force between two protons will be same .

Asked in: JEE Mains - Electrostatics - Test 1

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