The force constant of an oscillating simple pendulum is
The force constant of an oscillating simple pendulum is
Independent of mass of the bob as well as length of the pendulum
Inversely proportional to mass of the bob and length of the pendulum
Directly proportional to the mass of the bob
Directly proportional to length of the bob
Solution
For a simple pendulum, restoring torque equates the
$\begin{aligned}
& \tau=-m g L \sin \theta=I \alpha \\
& \Rightarrow \alpha=-\frac{m g L}{m L^2} \sin \theta \approx-\frac{g}{L} \theta \\
& \alpha \approx-\left(\frac{g}{L}\right) \theta \Rightarrow \alpha=-\omega^2 \theta=-\left(\frac{g}{L}\right) \theta
\end{aligned}$
Force constant of an oscillating simple pendulum is given by $k=m \omega^2$ $k \propto m$ and $k \propto \omega^2=\left(\frac{g}{L}\right)$
Therefore, force constant of an oscillating simple pendulum is directly proportional to the mass of the bob.