The following solutions were prepared by dissolving 10 g of glucose C 6 H 12 O 6 in 250 mL of water P 1 , 10…

Osmotic pressure $\left(\mathrm{\pi }\right)=\mathrm{CRT}$
At same temperature, $\mathrm{\pi }\propto \mathrm{C}$

Solution: $\left(1\right)$${\mathrm{C}}_1=\frac{10}{180}=\frac{10}{180}\times 4$

${\mathrm{C}}_1=\frac{250}{1000}=\frac{40}{180}=\frac{2}{9}$

${\mathrm{C}}_1=0.222\mathrm{M}$

Solution: $\left(2\right)$ ${\mathrm{C}}_2=\frac{10}{\frac{60}{\frac{250}{1000}}}=\frac{1}{6}\times 4=0.667\mathrm{M}$

Solution: $\left(3\right)$ ${\mathrm{C}}_3=\frac{10}{342}\times \frac{1000}{250}=0.1169\mathrm{M}$

$\because {\mathrm{C}}_2>{\mathrm{C}}_1>{\mathrm{C}}_3\therefore$ Hence, order: ${\mathrm{P}}_2>{\mathrm{P}}_1>{\mathrm{P}}_3$