The following reaction is a/an $\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br}…
The following reaction is a/an
$\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{KOH}} \\ & \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{KBr}+\mathrm{H}_2 \mathrm{O}\end{aligned}$
substitution reaction
addition reaction
electrophilic substitution reaction
elimination reaction
Solution
$\begin{aligned} \mathrm{CH}_3-\mathrm{CH}_2- & \mathrm{CH}_2-\mathrm{Br} \xrightarrow{\mathrm{KOH}} \\ & \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{KBr}+\mathrm{H}_2 \mathrm{O}\end{aligned}$
In the given reaction alkene is formed from alkane
by elimination of $-\mathrm{H}$ and $-\mathrm{Br}$. So, it is an elimination reaction.