
The following logic gate combination is equivalent to

- NAND gate
- OR gate
- XOR gate
- NOT gate
Solution
$\begin{aligned}
& \therefore \quad Y=\overline{A \cdot B} \cdot(A+B) \\
& \therefore \quad Y=(\bar{A}+\bar{B}) \cdot(A+B) \quad \cdots(\because \bar{A} \cdot \bar{B}=\bar{A}+\bar{B}) \\
& \therefore \quad Y=\bar{A} \cdot B+\bar{B} \cdot A \\
& \therefore \quad Y=A \cdot \bar{B}+B \cdot \bar{c}
\end{aligned}$
This représents XOR gate,
~Asked in: MHT CET 2023 (12 May Shift 1)