The focal distance of the point $(4,4)$ on the parabola with vertex at $((0,0)$ and symmetric about y-axis is
- 4
- 5
- $5 \sqrt{2}$
- $4 \sqrt{2}$
Solution
$x^{2}=4 y$
Focal distance = 5Asked in: MHT CET 2020 (13 Oct Shift 2)
$x^{2}=4 y$
Focal distance = 5Asked in: MHT CET 2020 (13 Oct Shift 2)