The first ionization energy of $\mathrm{Mg}, \mathrm{Al}, \mathrm{P}$ and S follows the order
- $\mathrm{Mg} < \mathrm{Al} < \mathrm{P} < \mathrm{S}$
- $\mathrm{Al} < \mathrm{Mg} < \mathrm{P} < \mathrm{S}$
- $\mathrm{Al} < \mathrm{Mg} < \mathrm{S} < \mathrm{P}$
- $\mathrm{Mg} < \mathrm{Al} < \mathrm{S} < \mathrm{P}$
Solution
$\begin{array}{llll}\text { Element } & P> & S> & M g> & A l \\ \left(I E_{1}ight) & 11.0 & 10.4 & 7.6 & 6.0\end{array}$ ^
Asked in: JEE-TOPICTESTS-CHEMISTRY
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