The favourable conditions for a spontaneous reaction are

The favourable conditions for a spontaneous reaction are
  1. $\mathrm{T} \Delta \mathrm{S}>\Delta \mathrm{H}, \Delta \mathrm{H}=+\mathrm{ve}, \Delta \mathrm{S}=+\mathrm{ve}$
  2. $\mathrm{T} \Delta \mathrm{S}>\Delta \mathrm{H}, \Delta \mathrm{H}=+\mathrm{ve}, \quad \Delta \mathrm{S}=-\mathrm{ve}$
  3. $\mathrm{T} \Delta \mathrm{S}=\Delta \mathrm{H}, \Delta \mathrm{H}=-\mathrm{ve}, \quad \Delta \mathrm{S}=-\mathrm{ve}$
  4. $\mathrm{T} \Delta \mathrm{S}=\Delta \mathrm{H}, \Delta \mathrm{H}=+\mathrm{ve}, \quad \Delta \mathrm{S}=+\mathrm{ve}$

Solution

$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}, \Delta \mathrm{H}$ is $+\mathrm{ve}$,
$\Delta \mathrm{S}$ is $+\mathrm{ve} ; \mathrm{T} \Delta \mathrm{S}>\Delta \mathrm{H}$
for spontaneous process. It will make $\Delta \mathrm{G},-\mathrm{ve}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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