The experimentally determined molar mass of a non-volatile solute, $\mathrm{BaCl}_2$ in water by Cottrell's…

The experimentally determined molar mass of a non-volatile solute, $\mathrm{BaCl}_2$ in water by Cottrell's method, is
  1. equal to the calculated molar mass
  2. more than the calculated molar mass
  3. less than the calculated molar mass
  4. double of the calculated molar mass

Solution

$\mathrm{BaCl}_2$ being ionic in nature, ionises completely to give $\mathrm{Ba}^{2+}$ and $2 \mathrm{Cl}^{-}(1+2=3)$ ions, i.e., number of particles increases in the solution. $\therefore \quad i=\frac{3}{1}=3=\frac{M_c}{M_o}$ (where, $M_c=$ calculated molar mass and $M_o=$ observed molar mass) $\begin{array}{ll} & 3=\frac{M_c}{M_o} \\ \text { or } & M_o=\frac{M_c}{3} \\ \text { i.e., } \quad & M_o < M_c\end{array}$ or observed molecular mass of $\mathrm{BaCl}_2$ is less than the calculated molecular mass.

Asked in: AP EAMCET 2012

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