The excess of pressure in a first soap bubble is three times that of other soap bubble. Then the ratio of…
The excess of pressure in a first soap bubble is three times that of other soap bubble. Then the ratio of the volume of first bubble to other is
- $1:3$
- $1:9$
- $27:1$
- $1:27$
Solution
$\begin{aligned} & \quad \Delta \mathrm{P} \propto \frac{1}{\mathrm{r}} \Rightarrow \frac{\mathrm{r}_1}{\mathrm{r}_2}=\frac{\Delta \mathrm{P}_2}{\Delta \mathrm{P}_1}=\frac{1}{3} \\ & \therefore \quad \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\left(\frac{\mathrm{r}_1}{\mathrm{r}_2}\right)^3=\frac{1}{27}\end{aligned}$
Asked in: MHT CET 2023 (09 May Shift 1)
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