The escape velocity of a body on the earth surface is $11.2 \mathrm{~km} / \mathrm{s}$. If the same body is projected upward with velocity $22.4 \mathrm{~km} / \mathrm{s}$, the velocity of this body at infinite distance from the centre of the earth will be

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Aicharya · Accepted Answer

$\begin{aligned} & V^{\prime 2}=V^2-V e^2 \ & V^{\prime}=\sqrt{V^2-V e^2} \ & =\sqrt{(22.4)^2-(11.2)^2} \ & V^{\prime}=11.2 \sqrt{3} \mathrm{~km} / \mathrm{s}\end{aligned}$

The escape velocity of a body on the earth surface is $11.2 \mathrm{~km} / \mathrm{s}$. If the same body is…

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