The escape velocity from the surface of earth of mass 'M' and radius 'R' is 'Ve'. The escape velocity from…

The escape velocity from the surface of earth of mass 'M' and radius 'R' is 'Ve'. The escape velocity from the surface of a planet whose mass and radius are 3 times that of the earth, will be
  1. $\mathrm{q} \mathbf{V}_{\mathrm{e}}$
  2. $3 \mathrm{Ve}$
  3. $\mathbf{V} \mathrm{e}$
  4. $12 \mathrm{Ve}$

Solution

$\mathrm{V}_{\mathrm{e}}=\sqrt{\frac{2 \mathrm{GM}}{\mathrm{R}}}$ $\mathrm{V}_{\mathrm{e}}^{\prime}=\sqrt{\frac{2 \mathrm{G} \times 3 \mathrm{M}}{3 \mathrm{R}}}=\sqrt{\frac{2 \mathrm{GM}}{\mathrm{R}}}=\mathrm{V}_{\mathrm{e}}$

Asked in: MHT CET 2020 (14 Oct Shift 1)

Practice more Gravitation questions on Aicharya