$\mathrm{Cu}_{2} \mathrm{S}+\mathrm{MnO}_{4}^{\ominus} \longrightarrow…
The equivalent weight of $\mathrm{Cu}_{2} \mathrm{S}$ is
- $\frac{M}{2}$
- $\frac{M}{6}$
- $\frac{M}{8}$
- $\frac{M}{4}$
Solution
$\mathrm{Cu}_{2}^{+1 \times 2} \longrightarrow 2 \mathrm{Cu}^{2+}+2 e^{-}$ $\left(' n^{\prime}=2ight)$ (oxidation)
$2 x=2 \quad \quad 2 x=4$
$\quad\mathrm{S}^{2-} \longrightarrow \quad\mathrm{SO}_{2}\quad+6 e^{-}\left('n^{\prime}=6ight)$ (oxidation)
$x=-2 \quad \quad x-4=0$
$\quad \quad \quad \quad \quad x=4$
Total $e^{-}=8$
$E w=\frac{M}{8}$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY