$\mathrm{Cu}_{2} \mathrm{S}+\mathrm{MnO}_{4}^{\ominus} \longrightarrow…

$\mathrm{Cu}_{2} \mathrm{S}+\mathrm{MnO}_{4}^{\ominus} \longrightarrow \mathrm{Cu}^{2+}+\mathrm{Mn}^{2+}+\mathrm{SO}_{2}$
The equivalent weight of $\mathrm{Cu}_{2} \mathrm{S}$ is
  1. $\frac{M}{2}$
  2. $\frac{M}{6}$
  3. $\frac{M}{8}$
  4. $\frac{M}{4}$

Solution

Both $\mathrm{Cu}^{1+}$ and $\mathrm{S}^{2-}$ in $\mathrm{Cu}_{2} \mathrm{~S}$ undergo oxidation.
$\mathrm{Cu}_{2}^{+1 \times 2} \longrightarrow 2 \mathrm{Cu}^{2+}+2 e^{-}$ $\left(' n^{\prime}=2ight)$ (oxidation)
$2 x=2 \quad \quad 2 x=4$
$\quad\mathrm{S}^{2-} \longrightarrow \quad\mathrm{SO}_{2}\quad+6 e^{-}\left('n^{\prime}=6ight)$ (oxidation)
$x=-2 \quad \quad x-4=0$
$\quad \quad \quad \quad \quad x=4$
Total $e^{-}=8$
$E w=\frac{M}{8}$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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