The equivalent weight of $\mathrm{Fe}$ in $\mathrm{Fe}_2 \mathrm{O}_3$ is $\left(\right.$ Atomic mass of…
The equivalent weight of $\mathrm{Fe}$ in $\mathrm{Fe}_2 \mathrm{O}_3$ is
$\left(\right.$ Atomic mass of $\mathrm{Fe}=56 \mathrm{~g} \mathrm{~mol}^{-1}$ )
$56.0$
$18.6$
$28.0$
$14.0$
Solution
In $\mathrm{Fe}_2 \mathrm{O}_3$, the oxidation state of $\mathrm{Fe}$ is +3 .
It means one-third of $\mathrm{Fe}$ mole is enough to
combine with $8 \mathrm{~g}$ of $\mathrm{O}_2$. Therefore, the equivalent
weight of iron in $\mathrm{Fe}_2 \mathrm{O}_3=\frac{55.8}{3}=18.6 \mathrm{~g}$