The equivalent resistance between $A$ and $B$ is $6 \Omega$. The value of $R_1$ is
The equivalent resistance between $A$ and $B$ is $6 \Omega$. The value of $R_1$ is

- $20 \Omega$
- $10 \Omega$
- $5 \Omega$
- $25 \Omega$
Solution
Here $2 \Omega$ and $3 \Omega$ resistances are short circuited, so circuit can be reduced as
$
\begin{array}{rlrl}
& & R_{A B} & =\frac{15 R_1}{15+R_1}=6 \\
\Rightarrow & 15 R_1-6 R_1 & =15 \times 6 \\
\Rightarrow & 9 R_1 =90 \\
\Rightarrow & R_1 =10 \Omega
\end{array}
$
Asked in: AP EAMCET 2018 (22 Apr Shift 1)
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