The equivalent resistance between A and B for the mesh shown in the figure is

Question

Aicharya · Accepted Answer

When the resistance is connected in series then the formula of equivalent resistance, $R = R_{1} + R_{2} + R_{3} + . . . . + R_{n}$ , but when they are connected in parallel then net resistance is, $\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . . + \frac{1}{R_{n}}$ , so in the above diagram the equivalent resistance will be,

,

in the above branch, resistance are connected in parallel, so new equivalent resistance will be,

So, the final resistance will be, $R_{n e t} = (4 + 4 + 8) Ω = 16 Ω$ .

The equivalent resistance between A and B for the mesh shown in the figure is

Solution