The equivalent conductance of $\frac{\mathrm{M}}{32}$ solution of a weak monobasic acid is $8.0…

The equivalent conductance of $\frac{\mathrm{M}}{32}$ solution of a weak monobasic acid is $8.0 \mathrm{~mho~} \mathrm{cm}^2$ and at infinite dilution is $400 \mathrm{~mho~} \mathrm{cm}^2$. The dissociation constant of this acid is
  1. $1.25 \times 10^{-5}$
  2. $1.25 \times 10^{-6}$
  3. $6.25 \times 10^{-4}$
  4. $1.25 \times 10^{-4}$

Solution

Degree of dissociation, $\alpha=\frac{\Lambda^c}{\Lambda^{\infty}}$ where, $\Lambda^c$ and $\Lambda^{\infty}$ are equivalent conductances at a given concentration and at infinite dilution respectively. $\Rightarrow \quad \alpha=\frac{8.0}{400}=2 \times 10^{-2}$ From Ostwald's dilution law (for weak monobasic acid) $\begin{aligned} \mathrm{K}_{\mathrm{a}} & =\frac{\mathrm{C} \alpha^2}{(1-\alpha)} \\ \text { or } \quad & \mathrm{C} \alpha^2 \\ & =\frac{1}{32}\left(2 \times 10^{-2}\right)^2 \\ \text { or } & =1.25 \times 10^{-5} \end{aligned}$

Asked in: NEET 2009 (Screening)

Practice more Electrochemistry questions on Aicharya