The equivalent conductance of NaCl at concentration C and at infinite dilution are λ C and λ…

1. ${\lambda }_{\text{C}}={\lambda }_{\infty }+\left(\text{B}\right)\text{C}$
2. ${\lambda }_{\text{C}}={\lambda }_{\infty }-\left(\text{B}\right)\text{C}$
3. ${\lambda }_{\text{C}}={\lambda }_{\infty }-\left(\text{B}\right)\sqrt{\text{C}}$
4. ${\lambda }_{\text{C}}={\lambda }_{\infty }+\left(\text{B}\right)\sqrt{\text{C}}$

Solution

Asked in: JEE Main 2014 (06 Apr)

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