The equivalent capacitance between points $\mathrm{A}$ and $\mathrm{B}$ as shown in figure is

Question

Aicharya · Accepted Answer

Equivalent circuit, using potential at $\mathrm{P}$ is same as at $\mathrm{A}$ and potential at $R$ is same as at $B$. This is equivalent to following: Therefore, the equivalent capacitance across AB is given by, $\Rightarrow C_{A B}=C+\frac{C}{2}+\frac{C}{2}=2 C$

The equivalent capacitance between points $\mathrm{A}$ and $\mathrm{B}$ as shown in figure is

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