The equation of wave is $\mathrm{Y}=6 \mathrm{sin}$ $\left(12 \pi t-0.02 \pi x+\frac{\pi}{3}\right)$ where '…

The equation of wave is $\mathrm{Y}=6 \mathrm{sin}$ $\left(12 \pi t-0.02 \pi x+\frac{\pi}{3}\right)$ where ' $x$ ' is in $m$ and ' $t$ ' in s. The velocity of the wave is
  1. $200 \mathrm{~m} / \mathrm{s}$
  2. $300 \mathrm{~m} / \mathrm{s}$
  3. $400 \mathrm{~m} / \mathrm{s}$
  4. $600 \mathrm{~m} / \mathrm{s}$

Solution

$\begin{aligned} & \text { Given: } y=6 \sin \left(12 \pi t-0.02 \pi x+\frac{\pi}{3}\right) \\ & \omega t=12 \pi t \\ & \Rightarrow \frac{2 \pi}{T}=12 \pi\end{aligned}$ $\begin{aligned} \therefore \quad \mathrm{T} & =\frac{1}{6} \\ \Rightarrow \mathrm{n} & =6 \end{aligned}$ Also given $\frac{2 \pi}{\lambda}=0.02 \pi$ $\therefore \quad \lambda=\frac{2}{0.02}=100$ From equation: $\mathrm{v}=\mathrm{n} \lambda$, we get $\begin{aligned} \mathrm{v} & =6 \times 100 \\ & =600 \mathrm{~m} / \mathrm{s} \end{aligned}$

Asked in: MHT CET 2023 (10 May Shift 2)

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