The equation of the plane through the intersection of the planes $x+y+z=1$ and $2 x+3 y-z+4=0$ and parallel…

The equation of the plane through the intersection of the planes $x+y+z=1$ and $2 x+3 y-z+4=0$ and parallel to $x-a x i s$ is
  1. $3 y+z-6=0$
  2. $3 y-z+6=0$
  3. $y-3 z+6=0$
  4. $y+3 z-6=0$

Solution

Required equation is $(x+y+z-1)+\lambda(2 x+3 y-z+4)=0$ $\Rightarrow(1+2 \lambda) x+(1+3 \lambda) y+(1-\lambda) z+(4 \lambda-1)=0$ But plane is parallel to the $\mathrm{x}$-axis $\begin{aligned} & \Rightarrow \lambda=-\frac{1}{2} \\ & \Rightarrow-\frac{1}{2} y+\frac{3}{2} z-3=0 \\ & \Rightarrow y-3 z+6=0 \end{aligned}$

Asked in: MHT CET 2022 (10 Aug Shift 1)

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