The equation of the locus of the foot of the perpendicular drawn from the centre of the ellipse…

The equation of the locus of the foot of the perpendicular drawn from the centre of the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ to any tangent of the ellipse is
  1. $\left(x^2+y^2\right)^2=a^2 x^2+b^2 y^2$
  2. $\left(x^2-y^2\right)^2=a^2 x^2+b^2 y^2$
  3. $\left(x^2+y^2\right)^2=a^2 x^2-b^2 y^2$
  4. $\left(x^2-y^2\right)^2=a^2 x^2-b^2 y^2$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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