The equation of the line perpendicular to $2 x-3 y+5=0$ and making an intercept 3 with positive Y-axis is

Question

Aicharya · Accepted Answer

Let the line be $3 x+2 y+\lambda=0$ Putting $x=0, y=\frac{-\lambda}{2}=3$ [given] $\Rightarrow \lambda=-6$ Hence the required line is $3 x+2 y-6=0$

Solution