The equation of the circle with centre $(0,2)$ and radius 2 is $x^2+y^2-m y=0$. The value of $m$ is

The equation of the circle with centre $(0,2)$ and radius 2 is $x^2+y^2-m y=0$. The value of $m$ is

  1. 1

  2. 2

  3. 4

  4. 3

Solution

Here $h=0, k=2$ and $r=2$. Therefore, the required equation of the circle is :
$(x-0)^2+(y-2)^2=(2)^2$
or $x^2+y^2-4 y+4=4$ or $x^2+y^2-4 y=0$

Asked in: BITSAT 2023 (Memory Based Paper 2)

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