The equation of the circle passing through $(2,0)$ and $(0,4)$ and having the minimum radius, is

The equation of the circle passing through $(2,0)$ and $(0,4)$ and having the minimum radius, is
  1. $x^2 + y^2 = 20$
  2. $x^2 + y^2 - 2x - 4y = 0$
  3. $x^2 + y^2 = 4$
  4. $x^2 + y^2 = 16$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2015

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