The equation of tangent at $\mathrm{P}(-4,-4)$ on the curve $x^{2}=-4 y$ is

Question

Aicharya · Accepted Answer

We have $x^{2}=-4 y \Rightarrow 2 x=-4 \frac{d y}{d x} \Rightarrow \frac{d y}{d x}=\frac{-x}{2}$ Hence slope of tangent at $P(-4,-4)$ is 2 . Hence required eq. of tangent is $y+4=2(x+4) \quad \Rightarrow 2 x-y+4=0$

The equation of tangent at $\mathrm{P}(-4,-4)$ on the curve $x^{2}=-4 y$ is

Solution