The equation of state for $5 \mathrm{~g}$ of oxygen at a pressure $P$ and temperature $T$, when occupying a…
The equation of state for $5 \mathrm{~g}$ of oxygen at a pressure $P$ and temperature $T$, when occupying a volume $V$, will be:
(where $R$ is the gas constant)
$P V=(5 / 32) R T$
$P V=5 R T$
$P V=(5 / 2) R T$
$P V=(5 / 16) R T$
Solution
We know that $P V=\underline{n} R T$
$\begin{gathered}
\therefore n=\frac{m}{\text { moleculer mass }}=\frac{5}{32} \\
\Rightarrow \quad P V=\left(\frac{5}{32}\right) R T
\end{gathered}$
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