The equation of motion of a particle executing simple harmonic motion is $4 \frac{\mathrm{d}^2…

The equation of motion of a particle executing simple harmonic motion is $4 \frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dt}^2}+\pi^2 \mathrm{y}=0$ where $y$ is in metres and $t$ is in seconds. The time period of oscillation of the particle is
  1. $1 \mathrm{~s}$
  2. $2 \mathrm{~s}$
  3. $3 \mathrm{~s}$
  4. $4 \mathrm{~s}$

Solution

Equation of motion: $ \begin{aligned} & 4 \frac{d^2 y}{d t^2}+\pi^2 y=0 \\ & \frac{d^2 y}{d t^2}+\frac{\pi^2}{4} y=0 \end{aligned} $ General equation of motion is $ \frac{d^2 y}{d t^2}+\omega^2 y=0 $ On compairing, $\omega^2=\frac{\pi^2}{2^2}$ $ \omega=\frac{\pi}{2} $ Time is given as : $T=\frac{2 \pi}{\omega}$ $ \begin{aligned} & T=\frac{2 \pi}{\pi} \times 2 \\ & T=4 \sec \end{aligned} $

Asked in: AP EAMCET 2023 (18 May Shift 2)

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