The equation of lines passing through $(5,3)$ and perpendicular to $2 x+y-7=0$ is

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Aicharya · Accepted Answer

$2 x+y+7=0 \Rightarrow P=(5,3)$ Required line is $b\left(x-x_1\right)-a\left(y-y_1\right)=0$ $\begin{aligned} 1(x-5)-2(y-3) & =0 \ x-5-2 y+6 & =0 \ x-2 y+1 & =0 \ \Rightarrow 2 y-x-1 & =0 \end{aligned}$ Hence, option (d) is correct.

The equation of lines passing through \((5,3)\) and perpendicular to \(2 x+y-7=0\) is

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