The equation of line passing through the points $(3,4,-7)$ and $(6,-1,1)$ is

The equation of line passing through the points $(3,4,-7)$ and $(6,-1,1)$ is
  1. $\frac{x-3}{3}=\frac{y-4}{-5}=\frac{z+7}{8}$
  2. $\frac{x-3}{3}=\frac{y-4}{5}=\frac{z+7}{8}$
  3. $\frac{x-3}{-3}=\frac{y-4}{-5}=\frac{z+7}{8}$
  4. $\frac{x-3}{3}=\frac{y-4}{-5}=\frac{z-7}{8}$

Solution

Required eq. of line is $\frac{x-3}{6-3}=\frac{y-4}{-1-4}=\frac{z+7}{1+7} \text { i.e. } \frac{x-3}{3}=\frac{y-4}{-5}=\frac{z+7}{8}$

Asked in: MHT CET 2020 (14 Oct Shift 2)

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