The equation of directrix of parabola $x^2+8 x+12 y+4=$ 0 is

The equation of directrix of parabola $x^2+8 x+12 y+4=$ 0 is
  1. $y+4=0$
  2. $y-1=0$
  3. $y-4=0$
  4. $y-2=0$

Solution

Given parabola is $x^2+8 x+12 y+4=0$ This can be written as $(x+4)^2=4(-3)(y-1)$ Here, $V=(-4,1)$ and equation of Directix, $Y=4$ or $y-4=0$

Asked in: AP EAMCET 2022 (08 Jul Shift 1)

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