The equation of circle with centre $(2,-3)$ and touching $X$-axis is

The equation of circle with centre $(2,-3)$ and touching $X$-axis is
  1. $x^2+y^2-4 x-6 y+4=0$
  2. $x^2+y^2-4 x-6 y-8=0$
  3. $x^2+y^2-4 x+6 y+4=0$
  4. $x^2+y^2+4 x-6 y+8=0$

Solution

(c) Centre is $(2,-3)$, circle touches $X$-axis, $ \therefore \text { Radius }=|-3|=3 \text {. } $ $\therefore$ Circle is $(x-2)^2+(y+3)^2=9$ $ \Rightarrow \quad x^2+y^2-4 x+6 y+4=0 $

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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