The equation of circle passing through the points $(1,-2)$ and $(4,-3)$ and whose centre lies on the line $3…
- $x^2+y^2+6 x-2 y-5=0$
- $x^2+y^2-6 x-2 y+5=0$
- $x^2+y^2+6 x+2 y-5=0$
- $x^2+y^2-6 x+2 y+5=0$
Solution
from (iii) + (iv)
$9 g=-27 \Rightarrow g=-3$
then $f=1$ and $c=5$
So, the required equation is $x^2+y^2-6 x+2 y+5=0$Asked in: MHT CET 2022 (06 Aug Shift 1)