The equation of a transverse wave travelling along a string is $y(x, t)=4.0 \sin \left[20 \times 10^{-3}…

The equation of a transverse wave travelling along a string is $y(x, t)=4.0 \sin \left[20 \times 10^{-3} x+600 t\right] \mathrm{mm}$, where $x$ is in mm and $t$ is in second. The velocity of the wave is :
  1. $-60 \mathrm{~m} / \mathrm{s}$
  2. $-30 \mathrm{~m} / \mathrm{s}$
  3. $+30 \mathrm{~m} / \mathrm{s}$
  4. $+60 \mathrm{~m} / \mathrm{s}$

Solution

$\begin{aligned}
& k=20 \times 10^{-3} \mathrm{~mm}^{-1}=20 \mathrm{~m}^{-1} \\ & w=600 \mathrm{~s}^{-1} \\ & v=\frac{W}{k}=\frac{600}{20}=30 \mathrm{~m} / \mathrm{s}
\end{aligned}$
and $x \& t$ carry same sign
Therefore $\mathrm{v}=-30 \mathrm{~m} / \mathrm{s}$

Asked in: JEE Main 2025 (23 Jan Shift 2)

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