The equation of a simple harmonic wave is given by $y=3 \sin \frac{\pi}{2}(50 t-x)$ where $x$ and $y$ are in…

The equation of a simple harmonic wave is given by $y=3 \sin \frac{\pi}{2}(50 t-x)$ where $x$ and $y$ are in metres and $t$ is in seconds. The ratio of maximum particle velocity to the wave velocity is
  1. $2 \pi$
  2. $\frac{3}{2} \pi$
  3. $3 \pi$
  4. $\frac{2}{3} \pi$

Solution

We know that $\begin{aligned} & v_{\text {max }}=a \omega \\ & v=n \lambda \\ & \therefore \quad \frac{v_{\max }}{v}=\frac{a \omega}{n \lambda} \\ & =\frac{a(2 \pi n)}{n \pi}=\frac{2 \pi a}{\lambda} \\ & =\frac{2 \pi a}{2 \pi / k} \\ & =k a=\frac{\pi}{2} \times 3 \\ & =\frac{3 \pi}{2} \\ & \end{aligned}$ ~

Asked in: NEET 2012 (Mains)

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