The equation of a line passing through the point of intersection of the lines $-2 y+8=0$ and $3 x-y+4=0$ and…

The equation of a line passing through the point of intersection of the lines $-2 y+8=0$ and $3 x-y+4=0$ and having $x$ and $y$ intercept zero is
  1. $4 x-5 y=0$
  2. $5 x-4 y=0$
  3. $5 x+4 y=0$
  4. $4 x+5 y=0$

Solution

$\begin{array}{l} x+2 y+8=0 \\ 3 x-y+4=0 \end{array}$ Solving we get; $x=\frac{-16}{7} ; y=\frac{-20}{7}$ line passing through $(0,0) \&\left(\frac{-16}{7}, \frac{-20}{7}\right) \&$ having $x$ \& $y$ intercept $5 x-4 y=0$

Asked in: MHT CET 2020 (14 Oct Shift 2)

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