The equation of a circle with centre \((5,4)\) and touch the \(Y\)-axis is
The equation of a circle with centre \((5,4)\) and touch the \(Y\)-axis is
\(x^2+y^2-10 x-8 y-16=0\)
\(x^2+y^2-10 x-8 y-61=0\)
\(x^2+y^2+10 x+8 y+16=0\)
\(x^2+y^2-10 x-8 y+16=0\)
Solution
Centre \((5,4)\) circle touches \(Y\)-axis
So, radius \(=5\) units
Equation of circle \(\Rightarrow(x-5)^2+(y-4)^2=5^2\)
\(\Rightarrow x^2+y^2-10 x-8 y+16=0\)