The entropy versus temperature plot for phases α and β at 1 bar pressure is given. S T and S 0 are entropies of the phases at temperatures T and 0   K , respectively. The transition temperature for α to β phase change is 600   K and C p , β - C p , α = 1…

Question

The entropy versus temperature plot for phases $α$ and $β$ at $1$ bar pressure is given. $S_{T}$ and $S_{0}$ are entropies of the phases at temperatures $T$ and $0 K$ , respectively.

The transition temperature for $α$ to $β$ phase change is $600 K$ and $C_{p, β} - C_{p, α} = 1 J {mol}^{- 1} K^{- 1}$ . Assume $(C_{p, β} - C_{p, α})$ is independent of temperature in the range of $200$ to $700 K . C_{p, α}$ and $C_{p, β}$ are heat capacities of $α$ and $β$ phases, respectively.

The value of entropy change,

S_{β} - S_{α}

(in

{Jmol}^{- 1} K^{- 1}

), at

300 K

is [Use:

\ln 2 = 0.69

0. Given:

S_{β} - S_{α} = 0

at

0 K

]

Aicharya · Accepted Answer

S = S 0 + &#8747; C p d T T S &#945; = S 0 + &#8747; C p &#945; d T T S &#946; = S 0 + &#8747; C p &#946; d T T Now, S &#946; - S &#945; = S 0 + &#8747; C p &#946; - C p &#945; d T T Given C p &#946; - C p &#945; = 1 S &#946; - S &#945; = lnT + C at any temperature of T S &#946; - S &#945; T 2 - S &#946; - S &#945; T 1 = lnT 2 - lnT 1 T 2 = 600 K &#160; , &#160; T 1 = 300 &#160; K &#160; and &#160; S &#946; - S &#945; = 1 &#160; at &#160; 600 &#160; K 1 - S &#946; - S &#945; 300 = ln 600 &#160; - ln 300 &#8658; S &#946; - S &#945; = 1 - 0 . 69 = 0 . 31

The entropy versus temperature plot for phases α and β at 1 bar pressure is given. S T and S 0 are…

Solution

The entropy versus temperature plot for phases &#945; and &#946; at 1 bar pressure is given. S T and S 0 are…

Solution

The entropy versus temperature plot for phases α and β at 1 bar pressure is given. S T and S 0 are…