The enthalpy of hydrogenation of cyclohexene is $-119.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$. If resonance…
- $-208.1 \mathrm{~kg} \mathrm{~mol}^{-1}$
- $-269.9 \mathrm{~kg} \mathrm{~mol}^{-1}$
- $-358.5 \mathrm{~kg} \mathrm{~mol}^{-1}$
- $-508.9 \mathrm{~kg} \mathrm{~mol}^{-1}$
Solution


$=-358.5 \mathrm{~kJ}$
The resonance energy provides extra stability to the benzene molecule so it has to be overcome for hydrogenation to take place. So $\Delta \mathrm{H}=-358.5-(-150.4)=-208.1 \mathrm{~kJ}$ *
Asked in: JEE-TOPICTESTS-CHEMISTRY