The energy stored in a strained wire is given by

The energy stored in a strained wire is given by
  1. \(\frac{1}{2} \times\) load \(\times\) extension
  2. \(\frac{1}{2} \times\) extension \(\times\) stress
  3. \(\frac{1}{2} \times\) stress \(\times\) strain
  4. \(\frac{1}{2} \times\) strain \(\times\) load

Solution

Energy stored in a strained wire is equal to work done by the load to increase the length of wire. \(\therefore\) Energy, \(U=\) Work done \(=\) Average force (load)\(\times\) Extension in the wire \(=\left(\frac{0+F}{2}\right) \times\) Extension \(=\frac{F}{2} \times\) Extension \(=\frac{1}{2} \times\) Load \(\times\) Extension

Asked in: AP EAMCET 2020 (21 Sep Shift 2)

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