The energy required to take a satellite to a height h above the Earth surface (radius of Earth = 6.4 ×…

$U_{\mathrm{surface} }+E_1=U_h$

$KE$ of satellite is zero at earth surface and at height $h$

$-\frac{G{M}_{e}m}{R_e}+E_1=-\frac{G{M}_{e}m}{\left(R_e+h\right)}$

$E_1=G{M}_{e}m\left(\frac{1}{R_e}-\frac{1}{R_e+h}\right)$

$E_1=\frac{G{M}_{e}m}{\left(R_e+h\right)}\times \frac{h}{R_e}$

Gravitational attraction $F_G=m{a}_C=\frac{m{v}^2}{\left(R_e+h\right)}$

$\Rightarrow \frac{m{v}^2}{\left(R_e+h\right)}=\frac{G{M}_{e}m}{{\left(R_e+h\right)}^2}$

$m{v}^2=\frac{G{M}_{e}m}{\left(R_e+h\right)}$

$E_2=\frac{m{v}^2}{2}=\frac{G{M}_{e}m}{2\left(R_e+h\right)}$

$E_1=E_2$

$\frac{h}{R_e}=\frac{1}{2}\Rightarrow h=\frac{R_e}{2}=3200 \mathrm{km}$